docs(uiux): UIUX 设计方案大改 + 5 份作业指导书对齐 + 开发任务文档
- UIUX 文档:填充 19 个缺口(多主体画像/健康度/AI+看板/增长域/洞察域/创始人端/OODA/助推/商密) - UIUX 文档:插入 6 个新章节(十四~十九),旧章节重编号为二十~三十一,更新目录和交叉引用 - 作业指导书 x5:导航改为 6 域分组,新增 Context Bar/工作模式/Insight Rail/决策线程/多工作区等 UI 概念 - 新建 docs/2-task-uiux.md:50 个代码落地开发任务,按 P0-P6 分优先级 + 8 Sprint 规划 - 后端/前端:大量新增模型、路由、组件(来自之前 Phase 开发)
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"""月报提交及时性追踪服务。
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统计企业月报提交延迟天数和数据质量评分。
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"""
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from datetime import datetime, timezone
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from sqlalchemy import select
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from sqlalchemy.ext.asyncio import AsyncSession
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from app.models.company import Company
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from app.models.report import MonthlyReport
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async def compute_timeliness(
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db: AsyncSession,
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tenant_id: str,
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company_id: str | None = None,
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) -> list[dict]:
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"""计算月报提交及时性和数据质量评分。
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返回每个企业每月的提交延迟天数和数据质量评分。
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延迟天数 = 实际提交日期 - 应提交日期(每月 10 号)。
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数据质量评分 = 结构化字段完整度(0-100)。
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"""
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query = (
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select(MonthlyReport, Company)
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.join(Company, MonthlyReport.company_id == Company.id)
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.where(Company.tenant_id == tenant_id)
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.where(MonthlyReport.status != "draft")
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)
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if company_id:
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query = query.where(MonthlyReport.company_id == company_id)
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result = await db.execute(query)
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rows = result.all()
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items: list[dict] = []
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for report, company in rows:
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if report.submitted_at is None:
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continue
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# 应提交日期:报告月份的下一个月 10 号
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due_year = report.period_year
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due_month = report.period_month + 1
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if due_month > 12:
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due_year += 1
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due_month = 1
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due_date = datetime(due_year, due_month, 10, tzinfo=timezone.utc)
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delay_days = max(0, (report.submitted_at - due_date).days)
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# 数据质量评分:结构化字段完整度
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structured = report.structured_data or {}
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expected_fields = [
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"revenue", "cash_balance", "burn_rate", "runway_months",
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"headcount", "key_metrics", "highlights", "concerns",
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]
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filled = sum(1 for f in expected_fields if structured.get(f) is not None)
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quality_score = round(filled / len(expected_fields) * 100, 1)
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items.append({
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"company_id": str(company.id),
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"company_name": company.name,
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"period_year": report.period_year,
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"period_month": report.period_month,
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"submitted_at": report.submitted_at.isoformat(),
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"delay_days": delay_days,
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"quality_score": quality_score,
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"status": report.status,
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})
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items.sort(key=lambda x: (x["company_name"], x["period_year"], x["period_month"]))
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return items
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